w^2+4w-380=0

Solution for w^2+4w-380=0 equation:

w^2+4w-380=0

a = 1; b = 4; c = -380;
Δ = b2-4ac
Δ = 42-4·1·(-380)
Δ = 1536
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1536}=\sqrt{256*6}=\sqrt{256}*\sqrt{6}=16\sqrt{6}$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-16\sqrt{6}}{2*1}=\frac{-4-16\sqrt{6}}{2}
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+16\sqrt{6}}{2*1}=\frac{-4+16\sqrt{6}}{2}
$